Planning kitchen appliances. How to proceed. Market is not clear

Respect! Then your cooktop has a boost of about 13,000 watts! Not bad!

Respect! Then your cooktop has a boost of about 13,000 watts! Not bad!

Respect! Then a typical kettle with 2kW takes 18 minutes to boil 1 liter of water? Is it perhaps possible to at least turn on your brain before posting something like that? Even without much knowledge, it should be obvious that the value is way off. Otherwise: water has a specific heat capacity of 4.182 kJ per kg and degree Kelvin, so to heat 1 kg of water (about 1 liter) from 20°C to 100°C requires 334.56 kJ. A cooktop with 13kW (your suggestion) delivers 13 kJ per second, so (without considering that the pot also heats up) the water boils in 25 seconds. The heat capacity of iron/steel is about 0.46 kJ/(K*kg), so a 2 kg heavy pot with 100°C also increases this by 20%, so to 30 seconds. On my boost with over 3kW, the water boils in roughly 2 minutes with a pot. The large heat of vaporization plays no role here for me, because once the water reaches the boiling point and 3kW+ power, it very reluctantly stays in the pot...

You wrote "weg". You can't talk your way out of this number anymore now.

But yes, of course you're right. Enthalpy of vaporization or not. As soon as the water boils, it jumps out of the pot in a high arc! Because your boost with 3,x kW of course goes completely differently than mine!

But luckily I have the Bratsensor now - at least the water doesn't burn anymore!

With pure evaporation, you would already be right (sorry). But just from the fact that water gas is invisible, while above the water alone there is already a lot of steam, you can see that a lot of non-boiled water is carried into the air. Otherwise, it would take much longer to reduce something when cooking. In the Lidl pan, this might also take a while with Boost for me. I also notice significant differences with my cookware. For example, the on/boil function only works with some pots.

But just from the fact that water gas cannot be seen, but directly above the water alone there is already a lot of vapor, you can see that a lot of unsaturated water is carried into the air.

Um, are there numbers for this?

As a rule, the visible vapor is condensation in the surrounding air. Before that, a completely normal phase transition has taken place.