AOLNCM
2016-09-01 16:39:00
- #1
Why? Delta from 23 degrees to 24 degrees = 1K. The 31-degree warm outside air also passes through the heat exchanger to the supply air openings. If 23-degree exhaust air is blown out and 31-degree outside air is taken in, then with 90% heat recovery afterwards it results in: 30.2 degrees exhaust air and 23.8 degrees supply air. I once rounded the difference up by about 25 percent to 24.0 (+1.0 instead of +0.8).
But one could do it for night cooling. Only then at night and not all day.
Wh = watt times hour. And if I calculate it per hour: Wh/h = watt.
Or in other words, 225 m3 air exchange per hour equals the following: (calculated with exact difference of 0.8K)
0.34 Wh/(m3*K) x 225 m3/h x 0.8K = 61.2 watts
This applies to the entire house. If the volume flow in the living room is now 50 m3/h, then the heat input in the living room within one hour is:
0.34 Wh/(m3*K) x 50 m3/h x 0.8K = 13.6 watts = 0.0136 kW
Thanks for the explanations.
- I was now able to understand where Delta T comes from, thanks.
- I know it this way, that even the highest level (party mode) is pre-set at about 3/4 of the max. power from the factory. If one wants to push 400 m³/h at night, an oversize system for many single-family homes is required, or the power of the highest level has to be raised to 100% at the expert level, which should be detrimental to the service life of the system. The power consumption during this time would correspond approximately to 2 to 3 lamps of 60 watts each switched on overnight.
- The unit watt times hour is correct, only in this calculation the night apparently lasts exactly one hour. However, if the night operation should last for e.g. 10 hours, then the total energy must be divided by the number of hours to get the power [watt].
@TE sorry for OT.